Write the first five terms of the geometric sequence if the nth term is given by 36(1/3)^n-1
Accepted Solution
A:
Answer:G1=36,G2=12,G3=4,G4=4/3,G5=4/9Step-by-step explanation:Since the nth term is given by;Gn= 36(1/3)^n-1, then, substitute the values of n as 1,2,3,4 and 5 to get the values of G1,G2,G3,G4 and G5 respectively.G1=36(1/3)^1-1 = 36G2= 36(1/3)^2-1= 12G3= 36(1/3)^3-1 = 4G4= 36(1/3)^4-1 = 4/3G5= 36(1/3)^5-1=4/9