MATH SOLVE

2 months ago

Q:
# What are the minimum, first quartile, median, third quartile, and maximum of the data set? 60, 50, 130, 200, 180, 150, 100, 140. I think the answer is:Minimum = 501st = 85Median = 1353rd = 167.50Maximum = 200However, none of the choices match my answer. What am I doing wrong?

Accepted Solution

A:

Answer:Minimum = 50First Quartile = 80Median = 135Third Quartile = 165Maximum = 200Step-by-step explanation:First, it is important to reorder our values into ascending order:50, 60, 100, 130, 140, 150, 180, 200You've correctly identified the minimum, median and maximum values, however the quartiles are where the mistakes lie.1. In order to calculate the first quartile, you need to look at where the median of the first half of the values is, ie. 50, 60, 100, 130The median will be the value between (or the average of) 60 and 100:(60 + 100)/2 = 80Thus, the first quartile is 80.2. In order to calculate the third quartile, we must find the median of the second half of the data set, ie. 140, 150, 180, 200The median will be the value between (or the average of) 150 and 180:(150 + 180)/2 = 165Thus the third quartile is 165.I find it's always a good idea to just draw this out and label the different values on paper to make it a bit easier.Hope that helped! If you find anything confusing just ask :)