You wish to ship six crude oil samples from your drill site to your laboratory. Each sample has a density of 0.8240 kg/L and fills a 1.090e-4 m3container. How much mass, X g , of crude oil will you be shipping?(HINT: |X| is near an order of magnitude of 102 g ).

Answer:total mass of 6 samples = 538.896 gin terms of X = 5.283 gStep-by-step explanation:Given:Number of crude oil samples = 6 Density of each sample = 0.8240 kg/LVolume filled by each sample = 1.09 × 10⁻⁴ m³now,1 m³ = 1000 Lthus, 1.09 × 10⁻⁴ m³ = 1.09 × 10⁻⁴ m³ × 1000 = 0.109 Lalso, Mass = Density × Volume orMass of each sample = 0.8240 × 0.109 = 0.089816 kgThus, total mass of 6 samples = Mass of each sample × 6 ortotal mass of 6 samples = 0.089816 kg × 6 = 0.538896 kgortotal mass of 6 samples = 538.896 gor in X = [tex]\frac{\textup{total mass of 6 samples}}{\textup{102}}[/tex] = 5.283 g