Find 3 consecutive integers where the sum of the first 2 equals 3 times the third. Please help

Answer: -5,-4,-3 Step-by-step explanation:Let n be an integer.The next integer would have to be n+1.The integer before n would have to be n-1.So the numbers in order are n-1, n , n+1The sum of the first 2 equals 3 times the third:n-1     +     n                      =     3(n+1)2n-1                                 =      3(n+1)2n-1=3n+3Subtract 2n on both sides     -1=n+3Subract 3 on both sides     -4=nIf n=-4then n-1=-5and n+1=-3So the three numbers are -5,-4,-3 .